NDA Maths Mock Test – 01 – Q27

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Question:

{C0 + 2C1 + 3C2 + …+ (n + 1)Cn} = ?

{C0 + 2C1 + 3C2 + …+ (n + 1)Cn} = ?

Options:

  • (n + 1) · 2n
  • (n + 2) · 2n-1
  • n · 2n-1
  • (n + 2) · 2n+1
  • (n + 1) · 2n
  • (n + 2) · 2n-1
  • n · 2n-1
  • (n + 2) · 2n+1

Correct Answer: b)

Explanation:

{C0 + 2C1 + 3C2 + …+ (n + 1)Cn} = (n + 2) · 2n-1

{C0 + 2C1 + 3C2 + …+ (n + 1)Cn} = (n + 2) · 2n-1

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