Question:
The sum of the squaresof the distances of a moving point from two fixed points (p, 0) and (-p, 0) is equal to a constant quantity 2λ2 , find the equation of the locus.
The sum of the squaresof the distances of a moving point from two fixed points (p, 0) and (-p, 0) is equal to a constant quantity 2λ2 , find the equation of the locus.
Options:
- x2 + y2 = lambda2 + p2
- x2 + y2 = lambda2 – p2
- x2 – y2 = lambda2 – p2
- x2 – y2 = lambda2 + p2
- x2 + y2 = lambda2 + p2
- x2 + y2 = lambda2 – p2
- x2 – y2 = lambda2 – p2
- x2 – y2 = lambda2 + p2
Correct Answer: b)
Explanation:
Let P(h, k) be any position of the mo√ing point and A(p, 0), B(-p, 0) be the gi√en points.
‘ Then,
‘ PA? + PB? = 2)?
= (h=p)? + (k= 0)2+(h +p)? + (k— 0)? =2)2
‘ = h? — 2ph +p? + K? + h2+2ph + p? + K2 = 2X2
hon a
‘ = 2h% + 2k? + 2p? = x2 ‘
= h? +k? =\ —p?
.
Hence, the locus of (h, k) is 2% + y? = A? — p2.
Let P(h, k) be any position of the mo√ing point and A(p, 0), B(-p, 0) be the gi√en points.
‘ Then,
‘ PA? + PB? = 2)?
= (h=p)? + (k= 0)2+(h +p)? + (k— 0)? =2)2
‘ = h? — 2ph +p? + K? + h2+2ph + p? + K2 = 2X2
hon a
‘ = 2h% + 2k? + 2p? = x2 ‘
= h? +k? =\ —p?
.
Hence, the locus of (h, k) is 2% + y? = A? — p2.