Question:
Consider the lines x = √3y and the circle x2 + y2 = 4. What is the area of the region in the first quadrant enclosed by the X-axis, the line x = √3y and the circle?
Consider the lines x = √3y and the circle x2 + y2 = 4. What is the area of the region in the first quadrant enclosed by the X-axis, the line x = √3y and the circle?
Options:
- (π/2 – √3/2) sq units
- (π/3 – √3/2) sq units
- (π/2 – 1) sq units
- (π/3 – 1/2) sq units
- (π/2 – √3/2) sq units
- (π/3 – √3/2) sq units
- (π/2 – 1) sq units
- (π/3 – 1/2) sq units
Correct Answer: b)
Explanation:
‘ The area is shaded as shown in the figure gi√en below
Y
EAR
“2 o√e bs a 0)
(0,0) x=V3
y
. : —_ 2
. .”. Required area = 0 Vai= de ‘
i = 3 √4 — 2? + 4sin (3)
— 34sin 1) – √BVT asin (9) !
1
a
‘ = (3 — 7) sq units
‘ 101.
©y”—4y’ +4y=0
‘
‘ The area is shaded as shown in the figure gi√en below
Y
EAR
“2 o√e bs a 0)
(0,0) x=V3
y
. : —_ 2
. .”. Required area = 0 Vai= de ‘
i = 3 √4 — 2? + 4sin (3)
— 34sin 1) – √BVT asin (9) !
1
a
‘ = (3 — 7) sq units
‘ 101.
©y”—4y’ +4y=0
‘