Question:
Complete the series:
\(\dfrac{8}{2}, \dfrac{27}{2}, \dfrac{64}{2}, \dfrac{125}{2}, ?\)
श्रृंखला पूरी कीजिए:
\(\dfrac{8}{2}, \dfrac{27}{2}, \dfrac{64}{2}, \dfrac{125}{2}, ?\)
Options:
- \(\dfrac{144}{2}\)
- \(\dfrac{216}{2}\)
- \(\dfrac{256}{2}\)
- \(\dfrac{343}{2}\)
- \(\dfrac{144}{2}\)
- \(\dfrac{216}{2}\)
- \(\dfrac{256}{2}\)
- \(\dfrac{343}{2}\)
Correct Answer: b)
Explanation:
Numerators are consecutive cubes:
\(2^3 = 8\), \(3^3 = 27\), \(4^3 = 64\), \(5^3 = 125\), \(6^3 = 216\).
Thus, the next fraction is \(\dfrac{216}{2}\).
अंश लगातार संख्याओं के घन हैं:
\(2^3 = 8\), \(3^3 = 27\), \(4^3 = 64\), \(5^3 = 125\), \(6^3 = 216\)।
अतः अगला पद \(\dfrac{216}{2}\) है।