SSC CHSL Similar 21 Nov S1 – Q071

Question:

If \(y = 2 + \sqrt{5}\), find the value of \(y + 1/y\).

यदि \(y = 2 + \sqrt{5}\) है, तो \(y + 1/y\) का मान ज्ञात कीजिए।

Options:

  • 3.47
  • 4.47
  • 5.44
  • 6.5
  • 3.47
  • 4.47
  • 5.44
  • 6.5

Correct Answer: b)

Explanation:

\(y = \sqrt{5} + 2\).
\(\dfrac{1}{y} = \dfrac{1}{\sqrt{5} + 2} = \sqrt{5} – 2\).
\(y + \dfrac{1}{y} = (\sqrt{5} + 2) + (\sqrt{5} – 2) = 2\sqrt{5} \approx 2 \times 2.236 = 4.472 \approx 4.47\).

\(y = \sqrt{5} + 2\).
\(\dfrac{1}{y} = \sqrt{5} – 2\).
\(y + \dfrac{1}{y} = 2\sqrt{5} \approx 2 \times 2.236 = 4.47\)।

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