Question:
Select the letter cluster that will replace the question mark (?) in the following series:
BCE, EGI, HLM, ?, NTY
निम्नलिखित श्रृंखला में प्रश्न चिह्न (?) को प्रतिस्थापित करने वाले अक्षर समूह का चयन करें:
BCE, EGI, HLM, ?, NTY
Options:
- KPS
- KOR
- KPT
- JPR
- KPS
- KOR
- KPT
- JPR
Correct Answer: a)
Explanation:
1st letter: B(2), E(5), H(8), ? -> +3 each time. \(8 + 3 = 11
ightarrow ext{K}\). (\(11 + 3 = 14
ightarrow ext{N}\)).
2nd letter: C(3), G(7), L(12), ? -> +4, +5, then +6: \(12 + 6 = 18 ?\) wait: C(3)->G(7) (+4), G(7)->L(12) (+5), L(12)->P(16) (+4?) or Q(17)? Look at T(20): from P(16) to T(20) is +4. So pattern is +4, +5, +4, +5 -> \(12 + 4 = 16
ightarrow ext{P}\), and \(16 + 4 = 20
ightarrow ext{T}\).
3rd letter: E(5), I(9), M(13), ? -> +4 each time: \(13 + 4 = 17
ightarrow ext{Q}\) or +4, +4, +6? Look at Y(25): from S(19) to Y(25) is +6. E(5)->I(9) (+4), I(9)->M(13) (+4), M(13)->S(19) (+6)? With KPS: B(2)->E(5)->H(8)->K(11)->N(14). C(3)->G(7)->L(12)->P(16)->T(20). E(5)->I(9)->M(13)->S(19)->Y(25).
Hence, the missing cluster is KPS (Option a).
पहला अक्षर: B(+3) -> E(+3) -> H(+3) -> K(+3) -> N
दूसरा अक्षर: C(+4) -> G(+5) -> L(+4) -> P(+4) -> T
तीसरा अक्षर: E(+4) -> I(+4) -> M(+6) -> S(+6) -> Y
अतः लुप्त समूह KPS है (विकल्प a)।