Question:
An organization is granted the IPv4 address block
192.168.10.0/24. It needs to create 6 subnets, each supporting at least 25 hosts. Which subnet mask should be utilized?
एक संगठन को IPv4 पता ब्लॉक
192.168.10.0/24 दिया गया है। इसे 6 सबनेट बनाने हैं, जिनमें से प्रत्येक में कम से कम 25 होस्ट होने चाहिए। किस सबनेट मास्क का उपयोग किया जाना चाहिए?
Options:
- 255.255.255.224 (/27)
- 255.255.255.240 (/28)
- 255.255.255.192 (/26)
- 255.255.255.248 (/29)
- 255.255.255.224 (/27)
- 255.255.255.240 (/28)
- 255.255.255.192 (/26)
- 255.255.255.248 (/29)
Correct Answer: a)
Explanation:
Requirements:
1. Need at least 6 subnets: \(2^s \ge 6 \implies s = 3\) bits borrowed from host portion.
2. Need at least 25 hosts per subnet: \(2^h – 2 \ge 25 \implies h = 5\) bits.
Total host bits originally in /24 = 8 bits. With \(s = 3\) and \(h = 5\), \(3 + 5 = 8\) bits perfectly matches!
New prefix length = \(24 + 3 = /27\).
Subnet mask =
1. Need at least 6 subnets: \(2^s \ge 6 \implies s = 3\) bits borrowed from host portion.
2. Need at least 25 hosts per subnet: \(2^h – 2 \ge 25 \implies h = 5\) bits.
Total host bits originally in /24 = 8 bits. With \(s = 3\) and \(h = 5\), \(3 + 5 = 8\) bits perfectly matches!
New prefix length = \(24 + 3 = /27\).
Subnet mask =
255.255.255.224.
गणना: 6 सबनेट के लिए 3 बिट्स (\(2^3 = 8\)) और 25 होस्ट के लिए 5 बिट्स (\(2^5 – 2 = 30\)) आवश्यक हैं। \(24 + 3 = /27\) सबनेट मास्क
255.255.255.224 बनता है।