Question:
The equation of a line is \(3x + 4y = 12\). What is the slope of the line?
एक रेखा का समीकरण \(3x + 4y = 12\) है। रेखा की प्रवणता (ढाल/slope) क्या है?
Options:
- −3/4
- 4/3
- −4/3
- 3/4
- −3/4
- 4/3
- −4/3
- 3/4
Correct Answer: a)
Explanation:
Rearranging the equation into slope-intercept form \(y = mx + c\):
\(4y = -3x + 12 \implies y = -\dfrac{3}{4}x + 3\).
Hence, the slope \(m = -3/4\).
समीकरण को \(y = mx + c\) रूप में लिखने पर:
\(4y = -3x + 12 \implies y = -\dfrac{3}{4}x + 3\)।
अतः प्रवणता \(m = -3/4\)।