A person travels from city P to city Q. If he travels at a speed of 60 km/h, he arrives 1 hour early. If he travels at a speed of 40 km/h, he arrives 1 hour late. What is the distance (in km) between city P and city Q ?

Questions :

A person travels from city P to city Q. If he travels at a speed of 60 km/h, he arrives 1 hour early. If he travels at a speed of 40 km/h, he arrives 1 hour late. What is the distance (in km) between city P and city Q ?

Options :

  • 240 km
  • 200 km
  • 220 km
  • 180 km

correct answer : a)

Explanation :
Let the distance between city P and city Q be d km. Since one journey results in arriving 1 hour early and the other results in arriving 1 hour late, the difference in travel times is 2 hours. Therefore,

d/40 − d/60 = 2

Taking LCM 120,

(3d − 2d)/120 = 2

d/120 = 2

d = 240 km

Hence, the distance between city P and city Q is 240 km. Option (b) 200 km, option (c) 220 km, and option (d) 180 km do not satisfy the given conditions and are therefore incorrect.

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