SSC_CGL_PYQ_12_Sep_2025_S3_Q5

Question:

If 4 ⊕ 3 = 19 and 5 ⊕ 2 = 17, then 6 ⊕ 4 = ?

यदि 4 ⊕ 3 = 19 और 5 ⊕ 2 = 17 है, तो 6 ⊕ 4 = ?

Options:

  • a) 24
  • b) 28
  • c) 34
  • d) 32
  • a) 24
  • b) 28
  • c) 34
  • d) 32

correct answer : c)

Explanation:

The given pattern is $a \oplus b = (a \times b) + (a + b)$.
For 4 ⊕ 3: $(4 \times 3) + (4 + 3) = 12 + 7 = 19$.
For 5 ⊕ 2: $(5 \times 2) + (5 + 2) = 10 + 7 = 17$.
Applying the same logic for 6 ⊕ 4:
$6 \oplus 4 = (6 \times 4) + (6 + 4) = 24 + 10 = 34$.

दिया गया पैटर्न $a \oplus b = (a \times b) + (a + b)$ है।
4 ⊕ 3 के लिए: $(4 \times 3) + (4 + 3) = 12 + 7 = 19$।
5 ⊕ 2 के लिए: $(5 \times 2) + (5 + 2) = 10 + 7 = 17$।
6 ⊕ 4 के लिए समान तर्क लागू करने पर:
$6 \oplus 4 = (6 \times 4) + (6 + 4) = 24 + 10 = 34$।

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