Question:
If sec 6A = cosec (A – 29°), where 2A is an acute angle, then the measure of ∠A = ___°.
यदि sec 6A = cosec (A – 29°) है, जहाँ 2A एक न्यून कोण है, तो ∠A का मान = ___°।
Options:
- a) 18
- b) 19
- c) 17
- d) 21
- a) 18
- b) 19
- c) 17
- d) 21
correct answer : c)
Explanation:
sec 6A = cosec (90 – 6A). So cosec (90 – 6A) = cosec (A – 29) => 90 – 6A = A – 29 => 7A = 119 => A = 17°.
sec 6A = cosec (90 – 6A). तो cosec (90 – 6A) = cosec (A – 29) => 90 – 6A = A – 29 => 7A = 119 => A = 17°.