NDA_Math_2025_Q42

Question:

What is (pq +qr + rp) equal to?

What is (pq +qr + rp) equal to?

Options:

  • a) -3 4
  • b) 0
  • c) 1 4
  • d) 3 4
  • a) -3 4
  • b) 0
  • c) 1 4
  • d) 3 4

correct answer : a)

Explanation:

pq + qr + rp = q(p + r) + rp
= -q2 + rp = – sin2 25° – sin 95°. sin 35°
(\ p + q + r = 0)
Oswaal NDA/NA Year-wise Solved Papers
= 1
2
[- 2sin225° – 2sin 95°. sin 35°]
=

1
2
[- 1 + cos 50° + cos 130° – cos 60°]
= 1
2
[- 1 + cos 50° – cos 50°- 1
2
]
= -3
4

pq + qr + rp = q(p + r) + rp
= -q2 + rp = – sin2 25° – sin 95°. sin 35°
(\ p + q + r = 0)
Oswaal NDA/NA Year-wise Solved Papers
= 1
2
[- 2sin225° – 2sin 95°. sin 35°]
=

1
2
[- 1 + cos 50° + cos 130° – cos 60°]
= 1
2
[- 1 + cos 50° – cos 50°- 1
2
]
= -3
4

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