Question:
The length of a simple pendulum is increased four times to its previous value while the mass is doubled. What is the ratio of the new and previous time period of the pendulum?
The length of a simple pendulum is increased four times to its previous value while the mass is doubled. What is the ratio of the new and previous time period of the pendulum?
Options:
- a) 3 : 1
- b) 2 : 5
- c) 2 : 1
- d) 3 : 2
- a) 3 : 1
- b) 2 : 5
- c) 2 : 1
- d) 3 : 2
correct answer : c)
Explanation:
Time period T = 2 * pi * sqrt(l / g). If length is increased 4 times, new time period T’ = 2 * pi * sqrt(4l / g) = 2T. Thus the ratio T’ : T = 2 : 1.
Time period T = 2 * pi * sqrt(l / g). If length is increased 4 times, new time period T’ = 2 * pi * sqrt(4l / g) = 2T. Thus the ratio T’ : T = 2 : 1.