Question :
If 4 − 2sin²θ − 5cosθ = 0, 0° < θ < 90°, then the value of sinθ + tanθ is :
Options :
- 3√2/2
- 3√3/2
- 3√2
- 2√3
correct answer : b)
(b) Put θ= 60°
sinθ + tanθ
√3/2 + √3 = 3√3/2
Question :
If 4 − 2sin²θ − 5cosθ = 0, 0° < θ < 90°, then the value of sinθ + tanθ is :
Options :
correct answer : b)
(b) Put θ= 60°
sinθ + tanθ
√3/2 + √3 = 3√3/2