Question:
In a ▵ ABC, (2 cos A)/(a) + (cos B)/(b) + (2 cos C)/(c) = (a)/(bc) + (b)/(ac) . Then, ▵ ABC is
In a ▵ ABC, (2 cos A)/(a) + (cos B)/(b) + (2 cos C)/(c) = (a)/(bc) + (b)/(ac) . Then, ▵ ABC is
Options:
- Cannot be determined
- a right angled triangle
- an equilateral triangle
- an isosceles triangle
- Cannot be determined
- a right angled triangle
- an equilateral triangle
- an isosceles triangle
Correct Answer: b)
Explanation:
. 2, 2_2
‘ Since, b” +c“ =a
1 Hence, ΔABC is a right angled triangle.
54
: s
_ 1-tai’a
. 2, 2_2
‘ Since, b” +c“ =a
1 Hence, ΔABC is a right angled triangle.
54
: s
_ 1-tai’a