Question:
If (cos A)/(a) = (cos B)/(b) = (cos C)/(c) and the side a = 2, then area of triangle is
If (cos A)/(a) = (cos B)/(b) = (cos C)/(c) and the side a = 2, then area of triangle is
Options:
- sqrt(3) sq units
- 2 sq units
- sqrt(3)/2 sq unit
- 1 sq unit
- sqrt(3) sq units
- 2 sq units
- sqrt(3)/2 sq unit
- 1 sq unit
Correct Answer: a)
Explanation:
1 By sine rule,
cosA _ cosB_ _ _cosC
KsnA ~~ KsinB ~~ KsinC
‘ = tan A = tan B = tan C i
1 i.e. Triangle is equilateral.
hon a
‘ A= 1la-asin60° = √3sq units -a=2 ‘
a=2
1 By sine rule,
cosA _ cosB_ _ _cosC
KsnA ~~ KsinB ~~ KsinC
‘ = tan A = tan B = tan C i
1 i.e. Triangle is equilateral.
hon a
‘ A= 1la-asin60° = √3sq units -a=2 ‘
a=2