SSC CHSL Premium Mock 04 – Q062

Question:

A mixture containing 30% alcohol is mixed with another mixture containing \(x\)% alcohol in the ratio 2 : 3. If the resulting mixture contains 24% alcohol, find the value of \(x\).

30% अल्कोहल वाले मिश्रण को \(x\)% अल्कोहल वाले दूसरे मिश्रण के साथ 2 : 3 के अनुपात में मिलाया जाता है। यदि परिणामी मिश्रण में 24% अल्कोहल है, तो \(x\) का मान ज्ञात कीजिए।

Options:

  • 18
  • 20
  • 22
  • 16
  • 18
  • 20
  • 22
  • 16

Correct Answer: b)

Explanation:

By the rule of alligation:
\(\dfrac{30 – 24}{24 – x} = \dfrac{3}{2} \implies \dfrac{6}{24 – x} = \dfrac{3}{2} \implies 3(24 – x) = 12 \implies 24 – x = 4 \implies x = 20\).

मिश्रण (Alligation) के नियम से:
\(\dfrac{30 – 24}{24 – x} = \dfrac{3}{2} \implies \dfrac{6}{24 – x} = \dfrac{3}{2} \implies 3(24 – x) = 12 \implies 24 – x = 4 \implies x = 20\)।

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top