DSSSB TGT CS Mock 02 – Question 126

In Boolean algebra, what is the dual of the expression \(X + YZ\)?

• \(X(Y + Z)\)
• \(X + (Y + Z)\)
• \(XY + Z\)
• \(\overline{X}(\overline{Y} + \overline{Z})\)

To find the dual of a Boolean expression:
– Interchange OR (+) and AND (\(\cdot\)) operators.
– Interchange 0 and 1.
– Variables remain uncomplemented.
Dual of \(X + Y \cdot Z\) is **\(X(Y + Z)\)** (Option a).