DSSSB TGT CS Mock 02 – Question 127

Question:

Match the logic gates in Column A with their universal/functional properties in Column B:

Column A (Gate) Column B (Property)
1. NAND Gate A. Parity checker / comparator
2. XOR Gate B. Universal gate
3. AND Gate C. Basic logic gate

कॉलम A के लॉजिक गेट्स का मिलान कॉलम B के गुणों से करें:

कॉलम A (गेट) कॉलम B (गुण)
1. NAND Gate A. पैरिटी चेकर
2. XOR Gate B. यूनिवर्सल गेट
3. AND Gate C. मूल लॉजिक गेट

Options:

  • 1-B, 2-A, 3-C
  • 1-A, 2-B, 3-C
  • 1-C, 2-A, 3-B
  • 1-B, 2-C, 3-A
  • 1-B, 2-A, 3-C
  • 1-A, 2-B, 3-C
  • 1-C, 2-A, 3-B
  • 1-B, 2-C, 3-A

Correct Answer: a)

Explanation:

1. NAND Gate is a Universal Gate (B).
2. XOR Gate is used for odd parity generation/checking and bit comparison (A).
3. AND Gate is a standard basic logic gate (C).
Hence, 1-B, 2-A, 3-C (Option a).

NAND यूनिवर्सल गेट है (1-B), XOR पैरिटी चेकर है (2-A), तथा AND मूल गेट है (3-C)। अतः सही मिलान 1-B, 2-A, 3-C है (विकल्प a)।

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