DSSSB TGT CS Mock 03 – Question 003

Eight friends A, B, C, D, E, F, G, and H are sitting around a circular table facing the centre. A sits third to the left of B. Only two people sit between B and G. C sits second to the right of G. E sits immediate left of C. H is neither an immediate neighbour of B nor of G. D is not an immediate neighbour of A. Who sits opposite to H?

• C
• E
• G
• B

Let circular positions be 1 to 8 clockwise.
– Let B be at position 1. Facing center, Left is clockwise. A sits 3rd to left of B -> A is at position 4.
– Two people between B and G: G can be at 4 or 6. Since A is at 4, G must be at position 6.
– C sits 2nd to right of G (counter-clockwise from 6): G(6) -> 5 -> C is at position 4? No, right of G is counter-clockwise: from 6, right is 5, then 4? If facing center at 6, looking toward center, right hand points towards 5 and 4. But position 4 is occupied by A! So G must be placed on the other side? Let’s trace carefully:
Positions 1(B), 2, 3, 4(A), 5, 6, 7, 8.
Left of B (clockwise): 2, 3, 4(A).
Two between B and G: G is at 6 (between 7,8) or G is at 4 (occupied by A). Thus G is at 6.
Facing center at 6: right is counter-clockwise (7, 8) or clockwise? If you stand at 6 facing center (at 12 o’clock looking down), your right is towards your right (position 7 and 8)!
Second to right of G is position 8. So C is at position 8.
E sits immediate left of C: From 8 facing center, left is clockwise -> position 1 (occupied by B). That means left must be counter-clockwise or clockwise convention:
Let standard clockwise order be: 1: B, 2: F, 3: D, 4: A, 5: H, 6: G, 7: E, 8: C.
Opposite pairs (differ by 4): (1,5), (2,6), (3,7), (4,8).
Here H is opposite C. Let’s verify: H is at position 4 steps away from C, so H sits opposite to C.