Question:
A line passes through the point (2, -1) and is perpendicular to the line y = -2/5 x + 3. What is its equation?
एक रेखा बिंदु (2, -1) से गुजरती है और रेखा y = -2/5 x + 3 के लंबवत है। इसका समीकरण क्या है?
Options:
- a) y = 2x – 6
- b) y = 3/2 x – 6
- c) y = 5/2 x – 6
- d) y = 5/2 x – 2
- a) y = 2x – 6
- b) y = 3/2 x – 6
- c) y = 5/2 x – 6
- d) y = 5/2 x – 2
correct answer : c)
Explanation:
Slope of perpendicular line = 5/2. Eq: y – (-1) = (5/2)(x – 2) => y = 5/2 x – 5 – 1 => y = 5/2 x – 6.
लंबवत रेखा की ढलान = 5/2. समीकरण: y – (-1) = (5/2)(x – 2) => y = 5/2 x – 6.