DSSSB TGT CS 2023 Shift 2 – Question 019

Question:

What approximate value should come in place of the question mark (?) in the following equation?

45.67 ÷ 22.89 – 56.69 + 23.89 × 13.37 = ?

निम्नलिखित समीकरण में प्रश्नवाचक चिह्न (?) के स्थान पर लगभग कितना मान आना चाहिए?

45.67 ÷ 22.89 – 56.69 + 23.89 × 13.37 = ?

Options:

  • 257
  • 345
  • 216
  • 378
  • 257
  • 345
  • 216
  • 378

Correct Answer: a)

Explanation:

Round each decimal number to its nearest integer for quick approximation:
– \(45.67 \approx 46\)
– \(22.89 \approx 23\)
– \(56.69 \approx 57\)
– \(23.89 \approx 24\)
– \(13.37 \approx 13\)

Substitute these approximate values into the equation:
\[? \approx 46 \div 23 – 57 + 24 \times 13\]
Apply the BODMAS rule:
1. Division: \(46 \div 23 = 2\)
2. Multiplication: \(24 \times 13 = 312\)
3. Addition and Subtraction: \(2 – 57 + 312 = 314 – 57 = 257\)
Hence, the approximate value is 257 (option a).

समीकरण के प्रत्येक दशमलव पद का निकटतम पूर्णांक में सन्निकटन करते हैं:
– \(45.67 \approx 46\)
– \(22.89 \approx 23\)
– \(56.69 \approx 57\)
– \(23.89 \approx 24\)
– \(13.37 \approx 13\)

समीकरण में सन्निकट मान रखने पर:
\[? \approx 46 \div 23 – 57 + 24 \times 13\]
BODMAS नियम लागू करने पर:
1. भाग: \(46 \div 23 = 2\)
2. गुणा: \(24 \times 13 = 312\)
3. जोड़ और घटाव: \(2 – 57 + 312 = 314 – 57 = 257\)
अतः लगभग मान 257 है (विकल्प a)।

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