DSSSB TGT CS Mock 02 – Question 103

Question:

How many 2-to-1 multiplexers are required to construct an 8-to-1 multiplexer?

एक 8-से-1 मल्टीप्लेक्सर बनाने के लिए कितने 2-से-1 मल्टीप्लेक्सर की आवश्यकता होगी?

Options:

  • 7
  • 8
  • 6
  • 4
  • 7
  • 8
  • 6
  • 4

Correct Answer: a)

Explanation:

To build an \(N\)-to-1 multiplexer using 2-to-1 MUXes:
Stage 1: \(8 / 2 = 4\) MUXes.
Stage 2: \(4 / 2 = 2\) MUXes.
Stage 3: \(2 / 2 = 1\) MUX.
Total required = \(4 + 2 + 1 = \textbf{7}\) (or formula \(N – 1 = 8 – 1 = 7\)) (Option a).

8-to-1 MUX बनाने के लिए: स्टेज 1 में 4, स्टेज 2 में 2 और स्टेज 3 में 1, कुल = \(4 + 2 + 1 = \textbf{7}\) (विकल्प a)।

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