Question:
What is the oxidation state of Vanadium in
V2O5?
What is the oxidation state of Vanadium in
V2O5?
Options:
- + 2
- + 4
- + 3
- + 5
- + 2
- + 4
- + 3
- + 5
Correct Answer: D) + 5
Explanation:
In V2O5, the oxidation state of O is -2. Let V be x. 2x + 5(-2) = 0 => 2x = 10 => x = +5.
In V2O5, the oxidation state of O is -2. Let V be x. 2x + 5(-2) = 0 => 2x = 10 => x = +5.