Question:
In the following redox reaction, which compound is acting as a reducing agent?
N2H4 + 2H2O2 → N2 + 4H2O
In the following redox reaction, which compound is acting as a reducing agent?
N2H4 + 2H2O2 → N2 + 4H2O
Options:
- H2O2
- N2H4
- N2
- H2O
- H2O2
- N2H4
- N2
- H2O
Correct Answer: N2H4
Explanation:
Reducing agent is the agent which oxidises itself and reduces other i.e., it loses its electron and increases its oxidation number while other elements gain electrons and decrease their oxidation number. N2H4 + 2H2O2 -> N2 + 4H2O. The oxidation number of N-atom increases from -2 to 0. Hence N2H4 is a reducing agent.
Reducing agent is the agent which oxidises itself and reduces other i.e., it loses its electron and increases its oxidation number while other elements gain electrons and decrease their oxidation number. N2H4 + 2H2O2 -> N2 + 4H2O. The oxidation number of N-atom increases from -2 to 0. Hence N2H4 is a reducing agent.