Question:
I. \(x^2 + 21x + 108 = 0\)
II. \(2y^2 + 53y + 350 = 0\)
I. \(x^2 + 21x + 108 = 0\)
II. \(2y^2 + 53y + 350 = 0\)
Options:
- (a) if x>y
- (b) if x≥y
- (c) if x
- (d) if x≤y
- (e) if x=y or no relation
- (a) यदि x>y
- (b) यदि x≥y
- (c) यदि x
- (d) यदि x≤y
- (e) यदि x=y या कोई संबंध नहीं
Correct Answer: a)
Explanation:
Correct Answer: (a) if x>y
x = -9, -12.
y = -14, -12.5.
Since x > y in all comparisons, x > y.
सही उत्तर: (a) यदि x>y