NDA Math Mock Test 03 – Question 114

Question:

The top of a hill observed from the top and bottom of a building of height \(h\) is at angles of elevation \(\alpha\) and \(\beta\) respectively. The height of the hill is:

\(h\) ऊँचाई की एक इमारत के शीर्ष और पाद से देखी गई पहाड़ी की चोटी के उन्नयन कोण क्रमशः \(\alpha\) और \(\beta\) हैं। पहाड़ी की ऊँचाई क्या है?

Options:

  • \(\frac{h\cot\beta}{\cot\beta – \cot\alpha}\)
  • \(\frac{h\cot\alpha}{\cot\alpha – \cot\beta}\)
  • \(\frac{h\cot\alpha}{\cot\beta – \cot\alpha}\)
  • None of the above
  • \(\frac{h\cot\beta}{\cot\beta – \cot\alpha}\)
  • \(\frac{h\cot\alpha}{\cot\alpha – \cot\beta}\)
  • \(\frac{h\cot\alpha}{\cot\beta – \cot\alpha}\)
  • उपरोक्त में से कोई नहीं

Correct Answer: b)

Explanation:

Let the height of the hill be \(H\) and the horizontal distance between building and hill be \(d\).
From the bottom of the building:
\[d = H\cot\beta\]
From the top of the building (height \(h\)):
\[d = (H – h)\cot\alpha\]
Equating both expressions for \(d\):
\[H\cot\beta = H\cot\alpha – h\cot\alpha \implies H(\cot\alpha – \cot\beta) = h\cot\alpha\]
\[H = \frac{h\cot\alpha}{\cot\alpha – \cot\beta}\]
Hence, the correct option is (b).

माना पहाड़ी की ऊँचाई \(H\) तथा क्षैतिज दूरी \(d\) है।
पाद से: \(d = H\cot\beta\)।
शीर्ष से: \(d = (H – h)\cot\alpha\)।
समीकरणों की तुलना करने पर:
\[H(\cot\alpha – \cot\beta) = h\cot\alpha \implies H = \frac{h\cot\alpha}{\cot\alpha – \cot\beta}\]
अतः सही विकल्प (b) है।

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