NDA Math Mock Test 03 – Question 77

Question:

The number of ways in which any four letters can be selected from the word ‘CORGOO’ is:

‘CORGOO’ शब्द से किन्हीं चार अक्षरों को चुनने के तरीकों की संख्या है:

Options:

  • 15
  • 11
  • 7
  • None of these
  • 15
  • 11
  • 7
  • इनमें से कोई नहीं

Correct Answer: c)

Explanation:

The word ‘CORGOO’ consists of letters: C(1), R(1), G(1), and O(3).
The distinct letters available are {C, R, G, O}.
We need to select 4 letters. We consider three mutually exclusive cases:
1. All 4 letters are distinct: Select 4 from {C, R, G, O} \(\implies {}^4C_4 = 1\) way.
2. 2 alike (OO) and 2 different: Select ‘OO’ (1 way) and 2 letters from {C, R, G} \(\implies {}^3C_2 = 3\) ways.
3. 3 alike (OOO) and 1 different: Select ‘OOO’ (1 way) and 1 letter from {C, R, G} \(\implies {}^3C_1 = 3\) ways.
Total number of selections \(= 1 + 3 + 3 = 7\).
Hence, the correct option is (c).

‘CORGOO’ में अक्षर: C(1), R(1), G(1), O(3) हैं।
चार अक्षर चुनने की स्थितियाँ:
1. चारों अक्षर भिन्न: {C, R, G, O} से 4 अक्षर चुनना = \({}^4C_4 = 1\)
2. 2 समान (OO) और 2 भिन्न: {C, R, G} से 2 अक्षर = \({}^3C_2 = 3\)
3. 3 समान (OOO) और 1 भिन्न: {C, R, G} से 1 अक्षर = \({}^3C_1 = 3\)
कुल तरीके = \(1 + 3 + 3 = 7\)।
अतः सही विकल्प (c) है।

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