Question:
If sin θ = 3 sin(θ + 2α) , then the value of tan(θ + α) + 2 tan α is equal to
If sin θ = 3 sin(θ + 2α) , then the value of tan(θ + α) + 2 tan α is equal to
Options:
- 1
- 2
- -1
- 0
- 1
- 2
- -1
- 0
Correct Answer: c)
Explanation:
‘
‘ sinf = 3sin(0 + 2c) ‘
ino _ 3
‘ = TS) =71
1 On applying componendo and di√idendo rule, we get
sin f+sin(0+2a) _ 341
sin 0—sin(0+2a) 3-1
61620) 9-20
‘ IN 2 sin (L020) cos £5x2)
2cos( 252) sin( £521)
i =3
sin(f+a) cosa _
= s(@ra)sma = 2
‘ = tan(f + a) – cota = —2
‘ = tan(f + a) = —2tana
= tan(6 + «) + 2tana =0
H 43. 1
Lo
1
‘
‘ sinf = 3sin(0 + 2c) ‘
ino _ 3
‘ = TS) =71
1 On applying componendo and di√idendo rule, we get
sin f+sin(0+2a) _ 341
sin 0—sin(0+2a) 3-1
61620) 9-20
‘ IN 2 sin (L020) cos £5x2)
2cos( 252) sin( £521)
i =3
sin(f+a) cosa _
= s(@ra)sma = 2
‘ = tan(f + a) – cota = —2
‘ = tan(f + a) = —2tana
= tan(6 + «) + 2tana =0
H 43. 1
Lo
1