NDA Maths Mock Test – 01 – Q50

If sin^-1 (x² – 7x + 12) = nπ, forall { n} in {Z} , then x equals

• 3
• -3
• 4
• -4

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‘ sin”! (2 – 7x +12) =n = x² – 7x + 12 = sin (nm), n € Z
! = x² Tx+12=0= x² -3x-4x +1x²0 ‘
= X(x-3)-4(x-3)=0= (x-3)(x-4)=0
MN
1 =x=3,4
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(¢) 30° < 6 < 45°
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