Question:
R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x – 3. Then, R-1 is
R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x – 3. Then, R-1 is
Options:
- {(11, 8), (13, 10)}
- {(10, 13), (12, 10)}
- {(8, 11), (10, 13)}
- {(10, 13), (8, 11), (12, 10)}
- {(11, 8), (13, 10)}
- {(10, 13), (12, 10)}
- {(8, 11), (10, 13)}
- {(10, 13), (8, 11), (12, 10)}
Correct Answer: c)
Explanation:
Since, y =x—3;
‘ Therefore, for x =11,y = 8.
‘ For x =12, y=9. But the √alue y = 9 does not exist in the gi√en set.
Forx=13,y=10.
‘ So, we ha√e R = (11, 8), (13, 10)
‘ Now, BR! = (8, 11), (10, 13).
Since, y =x—3;
‘ Therefore, for x =11,y = 8.
‘ For x =12, y=9. But the √alue y = 9 does not exist in the gi√en set.
Forx=13,y=10.
‘ So, we ha√e R = (11, 8), (13, 10)
‘ Now, BR! = (8, 11), (10, 13).