NDA Maths Mock Test – 01 – Q65

Question:

The eccentricity of the ellipse 9x2 + 25y2 – 18x – 100y – 116 = 0, is

The eccentricity of the ellipse 9x2 + 25y2 – 18x – 100y – 116 = 0, is

Options:

  • 25/16
  • 4/5
  • 5/4
  • 16/25
  • 25/16
  • 4/5
  • 5/4
  • 16/25

Correct Answer: b)

Explanation:

9×2 +25y2 – 18x – 100y – 116 = 0
‘ = 90% – 2x) + 25(y2 – dy) = 116
= 9×2 -2x + 1) + 25(y% – dy + 4) = 116 + 100 +9
1 = 9(x- 12 +25(y-2)% =25
91)? 25(y—2)°
i = el + od =1
2 2
1 = i) + Co) =1 \
Lo
1 Comparing it with = + x =1, we get
a?=25andb>=9
‘ a=5andb=3 i
1 Here, a > b, so the major and the minor axes of the ellipse are along the x-axis and y-axis,
hon a
‘ respecti√ely. ‘
— 1 ¥
) Now, e = 4/1 =
_ / 9
H =e=,/1— %
i Se=,/p i
1 M
>e=3
) 66. H
@y=0
‘

9×2 +25y2 – 18x – 100y – 116 = 0
‘ = 90% – 2x) + 25(y2 – dy) = 116
= 9×2 -2x + 1) + 25(y% – dy + 4) = 116 + 100 +9
1 = 9(x- 12 +25(y-2)% =25
91)? 25(y—2)°
i = el + od =1
2 2
1 = i) + Co) =1 \
Lo
1 Comparing it with = + x =1, we get
a?=25andb>=9
‘ a=5andb=3 i
1 Here, a > b, so the major and the minor axes of the ellipse are along the x-axis and y-axis,
hon a
‘ respecti√ely. ‘
— 1 ¥
) Now, e = 4/1 =
_ / 9
H =e=,/1— %
i Se=,/p i
1 M
>e=3
) 66. H
@y=0
‘

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