Question:
Options:
- 6√5 sq. units
- 5√5 sq. units
- 4 sq. units
- 3√5 sq. units
- 6√5 sq. units
- 5√5 sq. units
- 4 sq. units
- 3√5 sq. units
Correct Answer: d)
Explanation:
Area of A = ==
2 Ae
—- = ijk
‘ OAxXOB=1 2 3
‘ =i2-(-6) – j(1- (-9)) + k (-2- (-6))
hon a
2
‘ = 187 – 105 + 4k ‘
‘ = (/8% + (—10)2 + (4) !
1 = \/I80
A= 110 x OF
h Area of A = 3OA x OB 1
= 3 x 4/180
1 =3x6V5 I
Area of A = ==
2 Ae
—- = ijk
‘ OAxXOB=1 2 3
‘ =i2-(-6) – j(1- (-9)) + k (-2- (-6))
hon a
2
‘ = 187 – 105 + 4k ‘
‘ = (/8% + (—10)2 + (4) !
1 = \/I80
A= 110 x OF
h Area of A = 3OA x OB 1
= 3 x 4/180
1 =3x6V5 I