Question:
∫ [cos 2x / (sin x + cos x)2] dx is equal to
∫ [cos 2x / (sin x + cos x)2] dx is equal to
Options:
- -1/(sin x + cos x) + C
- 1/(sin x + cos x)2
- log |sin x – cos x| + C
- log |sin x + cos x| + C
- -1/(sin x + cos x) + C
- 1/(sin x + cos x)2
- log |sin x – cos x| + C
- log |sin x + cos x| + C
Correct Answer: d)
Explanation:
; i. cos x2
‘ Gi√en Integral is: rep√—— dz
_ cos 2z
Let = f raf &®
_ cos z—sin’ x
=f (sin z-+cos 2)? dz
ny (cos asin 7) (cos asin)
‘ (sin z+cos x)’
_ (cos z—sin x)
i Bb / (sin z+cos x) de
Put sin x + cos x =t = (cos X – sin x)dx = dt
i
aE
1 =logt+C
‘ =log sin x + cos x + C
I 95
X
(d)e” cotx+C 1
‘
; i. cos x2
‘ Gi√en Integral is: rep√—— dz
_ cos 2z
Let = f raf &®
_ cos z—sin’ x
=f (sin z-+cos 2)? dz
ny (cos asin 7) (cos asin)
‘ (sin z+cos x)’
_ (cos z—sin x)
i Bb / (sin z+cos x) de
Put sin x + cos x =t = (cos X – sin x)dx = dt
i
aE
1 =logt+C
‘ =log sin x + cos x + C
I 95
X
(d)e” cotx+C 1
‘