Question:
A car has an initial velocity of 12 m/s and is brought to rest over a distance of 45 m. The acceleration of the car is.
A car has an initial velocity of 12 m/s and is brought to rest over a distance of 45 m. The acceleration of the car is.
Options:
- a) + 1.6 m/s2
- b) +3 – 2 m/s2
- c) – 1.6 m/s2
- d) -0.8 m/s2
- a) + 1.6 m/s2
- b) +3 – 2 m/s2
- c) – 1.6 m/s2
- d) -0.8 m/s2
correct answer : c)
Explanation:
Using v^2 – u^2 = 2as. Here u = 12, v = 0, s = 45. 0 – 144 = 2 * a * 45 => 90a = -144 => a = -1.6 m/s^2.
Using v^2 – u^2 = 2as. Here u = 12, v = 0, s = 45. 0 – 144 = 2 * a * 45 => 90a = -144 => a = -1.6 m/s^2.