Question:
If two fair dice are tossed then what is the probability that the sum of the numbers on the faces of the dice is strictly greater than 7?
If two fair dice are tossed then what is the probability that the sum of the numbers on the faces of the dice is strictly greater than 7?
Options:
- a) 1 3
- b) 5 12
- c) 7 12
- d) 3 4
- a) 1 3
- b) 5 12
- c) 7 12
- d) 3 4
correct answer : b)
Explanation:
n(s) = 6 × 6 = 36
Sum strictly greater than 7
= {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5,3), (5, 4),
(5, 5), (5, 6), (6, 2),(6, 3), (6, 4), (6, 5),(6, 6)}
n(E) = 15
\ P(E) = 15
36
= 5
12
n(s) = 6 × 6 = 36
Sum strictly greater than 7
= {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5,3), (5, 4),
(5, 5), (5, 6), (6, 2),(6, 3), (6, 4), (6, 5),(6, 6)}
n(E) = 15
\ P(E) = 15
36
= 5
12