SSC CHSL 15 Nov S3 – Q045

Question:

If \(+ \to \div\), \(- \to \times\), \(\times \to -\), \(\div \to +\), evaluate:
\(36 + 6 – 2 \times 4 \div 2 = \text{?}\)

यदि \(+ \to \div\), \(- \to \times\), \(\times \to -\), \(\div \to +\) है, तो मान ज्ञात कीजिए:
\(36 + 6 – 2 \times 4 \div 2 = \text{?}\)

Options:

  • 10
  • 12
  • 14
  • 16
  • 10
  • 12
  • 14
  • 16

Correct Answer: a)

Explanation:

Substituting signs:
\(36 \div 6 \times 2 – 4 + 2\)
\(= 6 \times 2 – 4 + 2 = 12 – 4 + 2 = 10\).

चिह्न बदलने पर:
\(36 \div 6 \times 2 – 4 + 2 = 12 – 4 + 2 = 10\)।

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