SSC CHSL Similar 13 Nov S2 Set 2 – Q052

Question:

The average score of 4 tests is 72 marks. If the difference between the highest and lowest score is 28 and the remaining two scores are 70 and 74, find the highest score.

4 परीक्षणों का औसत स्कोर 72 अंक है। यदि उच्चतम और न्यूनतम स्कोर के बीच का अंतर 28 है और शेष दो स्कोर 70 और 74 हैं, तो उच्चतम स्कोर ज्ञात कीजिए।

Options:

  • 82
  • 84
  • 86
  • 88
  • 82
  • 84
  • 86
  • 88

Correct Answer: c)

Explanation:

Total score for 4 tests = \(4 \times 72 = 288\).
Sum of remaining two tests = \(70 + 74 = 144\).
Sum of highest (H) and lowest (L) = \(288 – 144 = 144\).
Given: \(H – L = 28\).
Adding both equations: \(2H = 172 \implies H = 86\).

4 परीक्षणों का कुल स्कोर = \(4 \times 72 = 288\)।
शेष दो का योग = \(70 + 74 = 144\)।
उच्चतम (H) और न्यूनतम (L) का योग = \(288 – 144 = 144\)।
अंतर: \(H – L = 28\)।
जोड़ने पर: \(2H = 172 \implies H = 86\)।

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