SSC IMD SA 2017 – Question 196

• Compilation error
• Runtime error
• Value of number is 10
• None of these

Detailed Explanation:

The correct answer is a) Compilation Error (कम्पाइलेशन एरर).

Code Examination:

class PrintTest {
    public static void main(String args[])
    {
        int num = 10;
        if (NUM < 100) {
            System.out.println("The value of num is" + num);
        }
    }
}

Reason for Compilation Error:

• Java is a strictly case-sensitive programming language. Identifiers, variable names, and keywords must precisely match their declaration in casing.
• In line 4, the variable is declared and initialized in lowercase: int num = 10;.
• In line 5, the condition attempts to reference the variable in uppercase: if (NUM < 100).
• Because no identifier named NUM exists in the local or enclosing scope, the Java compiler (javac) halts with a compile-time error:

error: cannot find symbol
  variable NUM
  location: class PrintTest

Because this fault is identified during syntax/semantic compilation before any bytecode execution can take place, the result is a Compilation Error.