SSC IMD SA Mock 01 – Question 180

Question:

Cyclomatic Complexity of a flow graph \(G\) with \(E\) edges and \(N\) nodes and 1 connected component is calculated as:

\(E\) किनारों और \(N\) नोड्स वाले एक प्रवाह ग्राफ का साइक्लोमैटिक जटिलता (Cyclomatic Complexity) सूत्र क्या है?

Options:

  • \(V(G) = E – N + 2\)
  • \(V(G) = E + N – 2\)
  • \(V(G) = E – N + 1\)
  • \(V(G) = N – E + 2\)
  • \(V(G) = E – N + 2\)
  • \(V(G) = E + N – 2\)
  • \(V(G) = E – N + 1\)
  • \(V(G) = N – E + 2\)

Correct Answer: a)

Explanation:

McCabe’s Cyclomatic Complexity formula for a single connected component is: **\(V(G) = E – N + 2\)** (or \(P + 1\) where \(P\) is predicate nodes) (Option a).

McCabe का साइक्लोमैटिक जटिलता सूत्र: **\(V(G) = E – N + 2\)** होता है (विकल्प a)।

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