Question:
If cos θ = (m²-n²) / (m²+n²), then what is tan θ?
यदि cos θ = (m²-n²) / (m²+n²), तो tan θ क्या है?
Options:
- a) 2mn / (m²-n²)
- b) (m²-n²) / 2mn
- c) (m²+n²) / 2mn
- d) 2mn / (m²+n²)
- a) 2mn / (m²-n²)
- b) (m²-n²) / 2mn
- c) (m²+n²) / 2mn
- d) 2mn / (m²+n²)
correct answer : a)
Explanation:
Base = m²-n², Hypotenuse = m²+n². Perpendicular = √((m²+n²)² – (m²-n²)²) = √(4m²n²) = 2mn. tan θ = Perpendicular/Base = 2mn / (m²-n²).
आधार = m²-n², कर्ण = m²+n²। लंब = √((m²+n²)² – (m²-n²)²) = √(4m²n²) = 2mn। tan θ = लंब/आधार = 2mn / (m²-n²)।