NDA Math Mock Test 02 – Question 14

Question:

What is the modulus of \(\left(\dfrac{\sqrt{-3}}{2} – \dfrac{1}{2}\right)^{200}\)?

\(\left(\dfrac{\sqrt{-3}}{2} – \dfrac{1}{2}\right)^{200}\) का मापांक क्या है?

Options:

  • \(\dfrac{1}{2}\)
  • 1
  • \(\dfrac{1}{4}\)
  • \(2^{200}\)
  • \(\dfrac{1}{2}\)
  • 1
  • \(\dfrac{1}{4}\)
  • \(2^{200}\)

Correct Answer: b)

Explanation:

\(\dfrac{\sqrt{-3}}{2} – \dfrac{1}{2} = -\dfrac{1}{2} + i\dfrac{\sqrt{3}}{2} = e^{i 2\pi/3} = \omega\).
Modulus of \(z = \omega^{200}\) is \(|z| = |\omega|^{200} = 1^{200} = 1\).

\(\dfrac{\sqrt{-3}}{2} – \dfrac{1}{2} = -\dfrac{1}{2} + i\dfrac{\sqrt{3}}{2} = \omega\)।
चूँकि \(|\omega| = 1\) होता है, अतः \(|\omega^{200}| = |\omega|^{200} = 1^{200} = 1\)।

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