NDA Math Mock Test 03 – Question 19
Question: Point (1, 2) relative to the circle \(x^2 + y^2 + 4x – 2y – 4 = 0\) is
Question: Point (1, 2) relative to the circle \(x^2 + y^2 + 4x – 2y – 4 = 0\) is
Question: The eccentricity of the hyperbola \(16x^2 – 9y^2 = 1\) is: अतिपरवलय \(16x^2 – 9y^2 = 1\) की उत्केंद्रता
Question: What is the period of the function \(f(x) = \sin x\)? फलन \(f(x) = \sin x\) की आवर्त अवधि
Question: The equation \(\tan^{-1}(1+x) + \tan^{-1}(1-x) = \frac{\pi}{2}\) is satisfied by: समीकरण \(\tan^{-1}(1+x) + \tan^{-1}(1-x) = \frac{\pi}{2}\) किससे संतुष्ट होता
Question: A tower of height 15 m stands vertically on the ground. From a point on the ground, the angle
Question: What is \(\lim_{\theta \to 0^+} \frac{\sqrt{1-\cos\theta}}{\theta}\) equal to? \(\lim_{\theta \to 0^+} \frac{\sqrt{1-\cos\theta}}{\theta}\) किसके बराबर है? Options: \(\sqrt{2}\) \(2\sqrt{2}\) \(\frac{1}{\sqrt{2}}\)
Question: If \(f(x) = |x| + |x-1|\), then which one of the following is correct? यदि \(f(x) = |x| +
Question: What is the derivative of \(\tan^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) with respect to \(\tan^{-1} x\)? \(\tan^{-1} x\) के सापेक्ष \(\tan^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) का अवकलज क्या
Question: The function \(f(x) = \frac{x^2}{e^x}\) is monotonically increasing if: फलन \(f(x) = \frac{x^2}{e^x}\) एकदिष्ट वर्धमान है यदि: Options: \(x
Question: What is \(\int \frac{\ln x}{x}\,dx\) equal to? \(\int \frac{\ln x}{x}\,dx\) किसके बराबर है? Options: \(\frac{(\ln x)^2}{2} + c\) \(\frac{\ln