Question:
If \(x + y = 10\) and \(x – y = 6\), find \((x^2 + y^2)/(x + y)\).
यदि \(x + y = 10\) और \(x – y = 6\) है, तो \((x^2 + y^2)/(x + y)\) का मान ज्ञात कीजिए।
Options:
- 6.8
- 7.2
- 7.6
- 8
- 6.8
- 7.2
- 7.6
- 8
Correct Answer: a)
Explanation:
\(x^2 + y^2 = \dfrac{(x + y)^2 + (x – y)^2}{2} = \dfrac{10^2 + 6^2}{2} = \dfrac{100 + 36}{2} = 68\).
Therefore, \(\dfrac{x^2 + y^2}{x + y} = \dfrac{68}{10} = 6.8\).
\(x^2 + y^2 = \dfrac{10^2 + 6^2}{2} = \dfrac{136}{2} = 68\)।
अतः \(\dfrac{x^2 + y^2}{x + y} = \dfrac{68}{10} = 6.8\)।