SSC GD 04 Feb 2025 Shift 1 – Question 51

Question:

Find the value of [(48 ÷ 8) × {49/7 + 40/4 × (7 − 3)}]

(a) 282

(b) 286

(c) 284

(d) 273

समीकरण [(48 ÷ 8) × {49/7 + 40/4 × (7 − 3)}] का मान ज्ञात कीजिए।

(a) 282

(b) 286

(c) 284

(d) 273

Correct Answer: (a)

Explanation:

Detailed Explanation:
(48 ÷ 8) = 6
(7 – 3) = 4
40/4 × 4 = 40
49/7 = 7
{7 + 40} = 47
6 × 47 = 282.

विस्तृत व्याख्या: BODMAS नियम से: 6 × (7 + 40) = 6 × 47 = 282।

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