Question:
Complete the series:
\(\dfrac{4}{3}, \dfrac{9}{3}, \dfrac{16}{3}, ?, \dfrac{36}{3}\)
श्रृंखला पूरी कीजिए:
\(\dfrac{4}{3}, \dfrac{9}{3}, \dfrac{16}{3}, ?, \dfrac{36}{3}\)
Options:
- \(\dfrac{20}{3}\)
- \(\dfrac{25}{3}\)
- \(\dfrac{30}{3}\)
- \(\dfrac{49}{3}\)
- \(\dfrac{20}{3}\)
- \(\dfrac{25}{3}\)
- \(\dfrac{30}{3}\)
- \(\dfrac{49}{3}\)
Correct Answer: b)
Explanation:
The numerators are squares of consecutive integers: \(2^2 = 4\), \(3^2 = 9\), \(4^2 = 16\), \(5^2 = 25\), \(6^2 = 36\).
Therefore, the missing term is \(\dfrac{25}{3}\).
अंशों में लगातार संख्याओं के वर्ग हैं: \(2^2 = 4\), \(3^2 = 9\), \(4^2 = 16\), \(5^2 = 25\), \(6^2 = 36\)।
अतः लुप्त पद \(\dfrac{25}{3}\) है।