SSC_CGL_PYQ_12_Sep_2025_S2_Q66

Question:

If x = √11, determine the value of x + 1/x.

यदि x = √11 है, तो x + 1/x का मान ज्ञात कीजिए।

Options:

  • a) 12√11 / 11
  • b) 11√11 / 12
  • c) 13√11 / 11
  • d) 14√11 / 11
  • a) 12√11 / 11
  • b) 11√11 / 12
  • c) 13√11 / 11
  • d) 14√11 / 11

correct answer : a)

Explanation:

Step 1: Substitute the given value of x into the expression.
\( x + \frac{1}{x} = \sqrt{11} + \frac{1}{\sqrt{11}} \)

Step 2: Rationalize the denominator of the second term.
\( \frac{1}{\sqrt{11}} = \frac{1 \times \sqrt{11}}{\sqrt{11} \times \sqrt{11}} = \frac{\sqrt{11}}{11} \)

Step 3: Add the two terms.
\( \sqrt{11} + \frac{\sqrt{11}}{11} = \frac{11\sqrt{11} + \sqrt{11}}{11} = \frac{12\sqrt{11}}{11} \).

चरण 1: व्यंजक में x का दिया गया मान रखें。
\( x + \frac{1}{x} = \sqrt{11} + \frac{1}{\sqrt{11}} \)

चरण 2: दूसरे पद के हर का परिमेयकरण करें。
\( \frac{1}{\sqrt{11}} = \frac{1 \times \sqrt{11}}{\sqrt{11} \times \sqrt{11}} = \frac{\sqrt{11}}{11} \)

चरण 3: दोनों पदों को जोड़ें。
\( \sqrt{11} + \frac{\sqrt{11}}{11} = \frac{11\sqrt{11} + \sqrt{11}}{11} = \frac{12\sqrt{11}}{11} \)।

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