SSC_CPO_Similar_09_Dec_2025_S1_Q130

Question:

Expand: (4x – 5)^2 = ?

विस्तार कीजिए: (4x – 5)^2 = ?

Options:

  • a) 16x^2 – 40x + 25
  • b) 16x^2 + 40x + 25
  • c) 16x^2 – 20x + 25
  • d) 8x^2 – 40x + 25
  • a) 16x^2 – 40x + 25
  • b) 16x^2 + 40x + 25
  • c) 16x^2 – 20x + 25
  • d) 8x^2 – 40x + 25

correct answer : a)

Explanation:

Using the algebraic identity (a – b)^2 = a^2 – 2ab + b^2:
Here, a = 4x and b = 5.
(4x – 5)^2 = (4x)^2 – 2 * (4x) * 5 + 5^2 = 16x^2 – 40x + 25.

बीजगणितीय सर्वसमिका (a – b)^2 = a^2 – 2ab + b^2 का उपयोग करने पर:
यहाँ, a = 4x और b = 5 है।
(4x – 5)^2 = (4x)^2 – 2 * (4x) * 5 + 5^2 = 16x^2 – 40x + 25.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top