SSC_CPO_Similar_09_Dec_2025_S1_Q146

Question:

If the area of the circular base of a hemisphere is 616 cm², find its volume.

यदि एक अर्धगोले के वृत्ताकार आधार का क्षेत्रफल 616 cm² है, तो इसका आयतन ज्ञात कीजिए।

Options:

  • a) 11498.67 cm³
  • b) 5749.33 cm³
  • c) 22997.33 cm³
  • d) 8624.00 cm³
  • a) 11498.67 cm³
  • b) 5749.33 cm³
  • c) 22997.33 cm³
  • d) 8624.00 cm³

correct answer : b)

Explanation:

Area of base = pi * r^2 = 616 cm²
=> (22/7) * r^2 = 616 => r^2 = 196 => r = 14 cm.
Volume of a hemisphere = (2/3) * pi * r^3
= (2/3) * (pi * r^2) * r
= (2/3) * 616 * 14 = 17248 / 3 ≈ 5749.33 cm³.

आधार का क्षेत्रफल = pi * r^2 = 616 cm²
=> (22/7) * r^2 = 616 => r^2 = 196 => r = 14 cm.
अर्धगोले का आयतन = (2/3) * pi * r^3
= (2/3) * (pi * r^2) * r
= (2/3) * 616 * 14 = 17248 / 3 ≈ 5749.33 cm³.

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